Jennifer had a question in the comments that’s something I’ve been thinking about recently, too. She wondered whether it was better, if your child already has 2 pair of glasses, to have one pair as the primary pair, and one set aside as a backup. Or does it make more sense to have both pairs as primary pairs, and let your child choose each morning which pair to wear?
For the past 18 months, Zoe has had two pair of glasses, and we’ve let her choose which pair to wear. It’s worked quite well, largely because she seems to like both pair equally, so they get pretty equal wear and tear. The lenses are less scratched, and the frames less beat up, because they’re both essentially getting worn half the time.
That all changed last week when we found out Zoe’s prescription had changed. I had planned to get the lenses replaced in one pair, and then when that pair was back, get new lenses for the second pair. The guy at the optical shop, though, told me that she was likely to outgrow her red glasses in around 6 months, and he didn’t think it would make sense to replace her lenses now, only to need to replace the frames and lenses again in a few months. So once her blue glasses come back with the updated prescription, we’ll have those as her primary glasses, with the red ones as back-up — the prescription change is small enough that the old prescription could be worn as a back up if need be.
I’d love to pick out a second pair of glasses for Zoe so that we can stay with the two pairs for her to choose from, since it’s worked so well. But ordering new lenses for one pair, and then a second whole new pair of glasses just isn’t in the cards for us right now. I guess I hadn’t really thought through the logistics of what happens with two pair when the prescription changes, but the frames don’t need to.
I’d love to hear thoughts on what you all are doing. Do you have a back up pair, or two pair that your child chooses from? Is it working well? What would you do if the money for additional pairs were not an issue (hey, I can dream, right?)